Algebra II Recipe: Solving Quadratic Equations by Factoring
By G Redden
- Find the largest number common to every coefficient or number.
Find the GCF of each variable.
- It will always be the variable raised to the smallest exponent.
Find the terms that the GCF would be multiplied by to equal the original polynomial.
- It looks like the distributive property when in factored form...GCF(terms).
3x² - 6x
2x² - 4x + 8
5x²y³ + 10x³y
B. Factoring the Difference of Two Squares
- The factors will always be (a + b)(a - b).
The "a" and "b" represent terms.
- "a" is the square root of the first term.
- "b" is the square root of the second term.
9x² - 49
121x² - 100
25x² - 64y²
C. Factoring a Perfect Square Trinomial
- Characteristics
- "ax²" term is a perfect square.
- "c" term is a perfect square.
- "c" term is positive.
- Factors into two identical binomials: (a + b)2.
- Steps to Factor
- Since it factors into two identical binomials - write it as (a ± b)2.
- "a" is the square root of the "ax2" term.
- "b" is the square root of the "c" term.
- The operation in the binomial factor is the same as the operation in front of the "x" term.
9x² - 30x + 25
4x² + 28xy + 49y²
2x² + 16x + 32
16x³ + 80x² + 100x
- Multiply "a" and "c".
Find two numbers that multiply to equal this product, but adds to equal "b".
- When a = 1 stop here. The two numbers chosen will be the numbers in the two binomial factors
Use these two numbers to rewrite the "x" term when writing out the problem again.
- When you have a choice, write the negative term first.
Group the first two terms and the last two terms together.
- If the third term from the left has subtraction in front, add the opposite before grouping.
Factor the GCF out of each set of parentheses.
- If you added the opposite in step 4, factor a negative GCF out of the second set of parentheses.
- The two GCFs make up one binomial factor and the common set of parentheses is the other binomial factor.
2x² - 7x - 4
x² + 6x - 16
2x² + 7x + 5
6x² - 13x + 5
- Set all terms equal to zero.
- Factor the quadratic completely.
- Set each factor having a variable equal to zero.
- Solve each equation.
- If we were to graph the quadratic equation, these values would be the x-intercepts. The numbers you get are the solutions.
2x² + 3x = 5
4x² + 2x = 0
3x² + 7x + 2 = 0
12x² - 5x - 3 = 0
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