Algebra II Recipe: Solving Inequalities with One Variable and Compound Sentences
By G Redden
- > means "is greater than"
- < means "is less than"
- ≥ means "is greater than or equal to"
- ≤ means "is less than or equal to"
- Perform the distributive property on each side.
- Combine like terms on each side.
- Add or subtract to get the variable terms on the same side. (Side of the largest coefficient.)
- Add or subtract to move the number term to the opposite side of the variable term.
- Multiply or divide to move the coefficient.
- If you multiply or divide both sides of an inequality by a negative number, the inequality symbol changes directions.
Solve and graph.
1.
x - 8 < 15
2.
4y + 3 > 7
3.
13 - 7n ≤ -8
4.
3x ≥ 11x + 4
** Make sure the variable is on the LEFT in all solutions.
- A solution with >:
- Graph an open circle on the number. (The number is not part of the solution.)
- A dark bar with an arrow goes to the right of the circle.
- A solution with <:
- Graph an open circle on the number. (The number is not part of the solution.)
- A dark bar with an arrow goes to the left of the circle.
- A solution with ≥:
- Graph a solid circle on the number. (The number is part of the solution.)
- A dark bar with an arrow goes to the right of the circle.
- A solution with ≤:
- Graph a solid circle on the number. (The number is part of the solution.)
- A dark bar with an arrow goes to the left of the circle.
Graph and Solve.
5.
2(3x - 2) < 4x + 8
6.
3(4x - 6) ≥ 6(x + 2)
7.
x + 3 ≤ 2(x - 4)
8.
-x + 4 < 2(x - 8)
9.
-2(x + 3) < 4x - 7
- Isolate the variable in the middle.
- Distribute in the middle if possible.
- Combine like terms in the middle if possible.
- Add or subtract the number term on each side of both inequality symbols.
- Multiply or divide by the coefficient on each side of both inequality symbols.
- If the solution contains greater than symbols, rotate the whole solution around to get less than symbols. (This would happen when you multiply or divide by a negative.)
- Graph the solution.
- One of the circles goes on each number in the solution.
- A darkened bar is graphed between the two circles.
10.
-4 < x + 2 ≤ 4
11.
-3 ≤ 2x + 1 ≤ 5
12.
17 < 5 - 3x < 29
** It's written like 8 + 2x < 6 OR 3x - 2 > 13
- Solve each inequality.
- The solution must be written with two inequalities connected with "OR".
- Graph each inequality.
- One of the circles goes on each number in the solution.
- The dark bar with an arrow is graphed in the direction indicated by the symbol with the number.
- If the dark bars are going toward each other, the answer is All Real Numbers, so you would graph a darkened bar over the entire number line.
13.
x - 4 ≤ 3 OR 2x > 18
14.
3x + 1 < 4 OR 2x - 5 > 7
15.
2x + 1 ≤ 7 OR -3x - 4 ≥ 2